Why does a capacitor behave like a pure conductor?

Resistance by the capacitor is inversely proportional to the frequency of the electric signal. Whenever any component offers zero resistance to an electric signal it behaves like a conductor therefore at a very high-frequency AC supply, the capacitor behaves like a pure conductor. Was this answer helpful?

How can a ladder be reduced to one capacitor?

A ladder of capacitors can be reduced to a single equivalent capacitor with capacitance C by connecting it to the three capacitors to the left of line AB as shown in Figure (26.31). The equivalent capacitance of the circuit shown in Figure (26.31) is also C. So the ladder can then be reduced to one capacitor with capacitance C.

How do you reduce the capacitance of the infinite series?

The capacitance of an infinite series is C. By cutting off the three capacitors to the left of line AB, the remainder of the ladder becomes an infinite series with a capacitance of C. Therefore, the ladder can be reduced to one capacitor with capacitance C connected to the three capacitors to the left of line AB, as shown in Figure (26.31).

How do I reduce the capacitance of a cap-probe input?

Use high impedance inputs on your actual cap-probe input and the non-inverting screen driver input. Not quite "doesn't see any capacitance", but rather "reduces current caused by the cable capacitance". If i=CdV/dt, then one can reduce the current by reducing C, or by reducing dV/dt.

Does a high impedance input reduce the capacitance of a cable?

Significant attenuation down the cable (losses) means it isn't as effective. Use high impedance inputs on your actual cap-probe input and the non-inverting screen driver input. Not quite "doesn't see any capacitance", but rather "reduces current caused by the cable capacitance".

What is the potential difference of a parallel plate capacitor?

The initial potential difference of a 2.00-nF parallel-plate capacitor is 100 V. The passage then discusses the work required and potential difference after the dielectric material is withdrawn, but it does not directly provide the answer to the original question.